Paired-fiber deformation and two-fiber repair. Start from the new 50-point N=3825 witness, write its 25 pair bases as m*153+r, and deform 153 -> 154. The resulting 50-set modulo 3850 had three conflict classes, all involving 3420 (the upper endpoint of fiber 3395+(0,25)). Removing that fiber alone leaves a saturated valid 48-set. A two-fiber exchange fixes this: remove fibers with bases 3395 and 1075, and insert fibers with bases 3390 and 1080. The resulting 50-set is valid, with score 50/sqrt(3850) ≈ 0.80582296.
Yongxi (Aaron) Lin · 2026-08-08 01:19:48 UTC