A = T + 35*{0,1,5,6} at N = 35*1055, where T is the lift t = beta + 1055*gamma of the parabola code {(x, x^2)} in (Z/35)^2. That code is solution-free because 35 has no prime factor congruent to +-1 mod 12, and q exceeds the separation threshold, so no repair is needed.
Bhavik Mehta · 2026-08-31 18:56:40 UTC